All elementary functions from a single binary operator
- SideQuark - 309888 sekunder sedanThis isn't unique, or even the least compute way to do this. For example, let f(x,y) = 1/(x-y). This too is universal. I think there's a theorem stating for any finite set of binary operators there is a single one replacing it.
write x#y for 1/(x-y).
x#0 = 1/(x-0) = 1/x, so you get reciprocals. Then (x#y)#0 = 1/((1/(x-y)) - 0) = x-y, so subtraction.
it's common problem to show in any (insert various algebraic structure here ) inverse and subtraction gives all 4 elementary ops.
I haven't checked this carefully, but this note seems to give a short proof (modulo knowing some other items...) https://dmg.tuwien.ac.at/goldstern/www/papers/notes/singlebi...
- DoctorOetker - 362598 sekunder sedanEDIT: please change the article link to the most recent version (as of now still v2), it is currently pointing to the v1 version which misses the figures.
I'm still reading this, but if this checks out, this is one of the most significant discoveries in years.
Why use splines or polynomials or haphazardly chosen basis functions if you can just fit (gradient descent) your data or wave functions to the proper computational EML tree?
Got a multidimensional and multivariate function to model (with random samples or a full map)? Just do gradient descent and convert it to approximant EML trees.
Perform gradient descent on EML function tree "phi" so that the derivatives in the Schroedinger equation match.
But as I said, still reading, this sounds too good to be true, but I have witnessed such things before :)
- entaloneralie - 363365 sekunder sedanThis is amazing! I love seeing FRACTRAN-shaped things on the homepage :) This reminds me of how 1-bit stacks are encoded in binary:
A stack of zeros and ones can be encoded in a single number by keeping with bit-shifting and incrementing.
I use something not too far off for my daily a programming based on a similar idea:Pushing a 0 onto the stack is equivalent to doubling the number. Pushing a 1 is equivalent to doubling and adding 1. Popping is equivalent to dividing by 2, where the remainder is the number.Rejoice is a concatenative programming language in which data is encoded as multisets that compose by multiplication. Think Fractran, without the rule-searching, or Forth without a stack.
- karpathy - 319100 sekunder sedanAll possible 36 distinct level-2 eml functions of one variable (the first 18 of them with entirely Real outputs, the other 18 with "intermediate" complex-valued components):
- eugene3306 - 358386 sekunder sedanThis makes a good benchmark LLMs:
``` look at this paper: https://arxiv.org/pdf/2603.21852
now please produce 2x+y as a composition on EMLs ```
Opus(paid) - claimed that "2" is circular. Once I told it that ChatGPT have already done this, finished successfully.
ChatGPT(free) - did it from the first try.
Grok - produced estimation of the depth of the formula.
Gemini - success
Deepseek - Assumed some pre-existing knowledge on what EML is. Unable to fetch the pdf from the link, unable to consume pdf from "Attach file"
Kimi - produced long output, stopped and asked to upgrade
GLM - looks ok
- lioeters - 362591 sekunder sedan> A calculator with just two buttons, EML and the digit 1, can compute everything a full scientific calculator does
Reminds me of the Iota combinator, one of the smallest formal systems that can be combined to produce a universal Turing machine, meaning it can express all of computation.
- testaccount28 - 357987 sekunder sedanderivation of -x seems wrong. we can look at the execution trace on a stack machine, but it's actually not hard to see. starting from the last node before the output, we see that the tree has the form
and the claim is that, after it's expanded, z will be such that this whole thing is equal to -x. but with some algebra, this is happening only ifeml(z, eml(x, 1)) = e^z - ln(eml(x, 1)) = e^z - ln(e^x) = e^z - x
and there is no complex number z that satisfies this equation. indeed if we laboriously expand the given formula for z (the left branch of the tree), we see that it goes through ln(0), and compound expressions.e^z = 0,x^-1 has the same problem.
both formulae work ...sort of... if we allow ln(0) = Infinity and some other moxie, such as x / Infinity = 0 for all finite x.
- nullwiz - 321710 sekunder sedanI made https://github.com/nullwiz/emlvm/tree/main yesterday, for fun :^)
- js8 - 316485 sekunder sedanThat's quite interesting.
Few ideas that come to my mind when reading this:
1. One should also add absolute value (as sqrt(x*x)?) as a desired function and from that min, max, signum in the available functions. Since the domain is complex some of them will be a bit weird, I am not sure.
2. I think, for any bijective function f(x) which, together with its inverse, is expressible using eml(), we can obtain another universal basis eml(f(x),f(y)) with the added constant f^-1(1). Interesting special case is when f=exp or f=ln. (This might also explain the EDL variant.)
3. The eml basis uses natural logarithm and exponent. It would be interesting to see if we could have a basis with function 2^x - log_2(y) and constants 1 and e (to create standard mathematical functions like exp,ln,sin...). This could be computationally more feasible to implement. As a number representation, it kinda reminds me of https://en.wikipedia.org/wiki/Elias_omega_coding.
4. I would like to see an algorithm how to find derivatives of the eml() trees. This could yield a rather clear proof why some functions do not have indefinite integrals in a symbolic form.
5. For some reason, extending the domain to complex numbers made me think about fuzzy logics with complex truth values. What would be the logarithm and exponential there? It could unify the Lukasiewicz and product logics.
- krick - 363136 sekunder sedan> using EML trees as trainable circuits ..., I demonstrate the feasibility of exact recovery of closed-form elementary functions from numerical data at shallow tree depths up to 4
That's awesome. I always wondered if there is some way to do this.
- ks2048 - 310528 sekunder sedanThis looks interesting. I haven't looked in-detail, but my first thought is - why hasn't this been found in the past? Surely, people have been interested kind of question for awhile?
- qiller - 363539 sekunder sedanFor completeness, there is also Peirce’s arrow aka NOR operation which is functionally complete. Fun applications iirc VMProtect copy protection system has an internal VM based on NOR.
Quick google seach brings up https://github.com/pr701/nor_vm_core, which has a basic idea
- CGamesPlay - 352798 sekunder sedanI made a fun marimo notebook to try and derive these myself. I structured each cell in order based on the diagram at the end of the paper. It uses Sympy to determine if the function is correct or not.
https://gist.github.com/CGamesPlay/9d1fd0a9a3bd432e77c075fb8...
- lmf4lol - 330908 sekunder sedanStupid question maybe (I am no mathematician), but aren't exp and ln really primitives? Aren't they implemented in terms of +,-,/,* etc? Or do we assume that we have an infinite lookup table for all possible inputs?
- - 327729 sekunder sedan
- Aardwolf - 312702 sekunder sedanInteresting!
One thing I wonder now: NAND is symmetric while this isn't, could something similar be found where function(x, y) = function(y, x)?
- evnix - 354313 sekunder sedanCan someone explain how is this different from lambda calculus, it seems like you can derive the same in both. I don't understand both well enough and hence the question.
- simplesighman - 364414 sekunder sedan> For example, exp(x)=eml(x,1), ln(x)=eml(1,eml(eml(1,x),1)), and likewise for all other operations
I read the paper. Is there a table covering all other math operations translated to eml(x,y) form?
- rurban - 318095 sekunder sedanI like this guy. https://th.if.uj.edu.pl/~odrzywolek/homepage/index.html
- vintermann - 340776 sekunder sedanI'm way too unschooled to say if it's important or not, but what really excites me is the Catalan structure ("Every EML expression is a binary tree [...] isomorphic to well-studied combinatorial objects like full binary trees and Catalan objects").
So, what happens if you take say the EML expression for addition, and invert the binary tree?
- notorandit - 358580 sekunder sedanNot sure it really compares to NAND() and the likes.
Simply because bool algebra doesn't have that many functions and all of them are very simple to implement.
A complex bool function made out of NANDs (or the likes) is little more complex than the same made out of the other operators.
Implementing even simple real functions out of eml() seems to me to add a lot of computational complexity even with both exp() and ln() implemented in hardware in O(1). I think about stuff sum(), div() and mod().
Of course, I might be badly wrong as I am not a mathematician (not even by far).
But I don't see, at the moment, the big win on this.
- tgtweak - 326059 sekunder sedanThis could have some interesting hardware implications as well - it suggests that a large dedicated silicon instruction set could accelerate any mathematical algorithm provided it can be mapped to this primitive. It also suggests a compiler/translation layer should be possible as well as some novel visualization methods for functions and methods.
- prvc - 358945 sekunder sedanThis is neat, but could someone explain the significance or practical (or even theoretical) utility of it?
- boutell - 318457 sekunder sedanHalfway through I was imagining aliens to whom this operator comes naturally and our math is weird. By the end I found out that we might be those aliens.
- mmastrac - 325475 sekunder sedanI couldn't find any information on this, but is it possible that given how nicely exponentiation and logarithms differentiate and integrate, is it possible that this operator may be useful to simplify the process of finding symbolic solutions to integrals and derivatives?
- selcuka - 366629 sekunder sedanSo, like brainf*ck (the esoteric programming language), but for maths?
- jekude - 365528 sekunder sedanWhat would physical EML gates be implemented in reality?
Posts like these are the reason i check HN every day
- drdeca - 319521 sekunder sedan“ Elementary functions, for many students epitomized by the dreaded sine and cosine, ” dreaded?
- tripdout - 365376 sekunder sedanInteresting, but is the required combination of EML gates less complex than using other primitives?
- peterlk - 366659 sekunder sedanReminds me a bit of the coolest talk I ever got to see in person: https://youtu.be/FITJMJjASUs?si=Fx4hmo77A62zHqzy
It’s a derivation of the Y combinator from ruby lambdas
- hughw - 332237 sekunder sedaneml(x, y) pronounced... "email"?
- theodorethomas - 318265 sekunder sedanI wonder how this combines with Richardson's Theorem.
- - 328305 sekunder sedan
- ryanhiebert - 333649 sekunder sedanI’d be really interested in an analysis of tau in light of this discovery. Would tau fit more naturally here than pi, as it does in other examples?
- nonfamous - 366304 sekunder sedanHow would an architecture with a highly-optimized hardware implementation of EML compare with a traditional math coprocessor?
- hyperhello - 365277 sekunder sedan> eml(x,y)=exp(x)-ln(y)
Exp and ln, isn't the operation its own inverse depending on the parameter? What a neat find.
- khelavastr - 349094 sekunder sedanIs the the same as saying everything can be made from nand gates?
- measurablefunc - 312274 sekunder sedanI guess you folks don't know about iota & jot: https://en.wikipedia.org/wiki/Iota_and_Jot
- psychoslave - 356258 sekunder sedanVery nice, though I'm not found of the name.
What comes to my mind as an alternative which I would subjectivity finer is "axe". Think axiom or axiology.
Anyone with other suggestions? Or even remarks on this one?
- pveierland - 345409 sekunder sedanGot curious to see whether SymPy could be used to evaluate the expressions, so I used Claude Code to build a quick evaluator. Numeric and symbolic results appear to agree:
nix run github:pveierland/eml-eval EML Evaluator — eml(x, y) = exp(x) - ln(y) Based on arXiv:2603.21852v2 by A. Odrzywołek Constants ------------------------------------------------------------------------------ 1 K=1 d=0 got 1 expected 1 sym=ok num=ok [simplify] e K=3 d=1 got 2.718281828 expected 2.718281828 sym=ok num=ok [simplify] 0 K=7 d=3 got 0 expected 0 sym=ok num=ok [simplify] -1 K=17 d=7 got -1 expected -1 sym=ok num=ok [simplify] 2 K=27 d=9 got 2 expected 2 sym=ok num=ok [simplify] -2 K=43 d=11 got -2 expected -2 sym=ok num=ok [simplify] 1/2 K=51 d=15 got 0.5 expected 0.5 sym=ok num=ok [simplify] -1/2 K=67 d=17 got -0.5 expected -0.5 sym=ok num=ok [simplify] 2/3 K=103 d=19 got 0.6666666667 expected 0.6666666667 sym=ok num=ok [simplify] -2/3 K=119 d=21 got -0.6666666667 expected -0.6666666667 sym=ok num=ok [simplify] sqrt2 K=85 d=21 got 1.414213562 expected 1.414213562 sym=ok num=ok [simplify] i K=75 d=19 got i expected i sym=ok num=ok [i²=-1, simplify] pi K=153 d=29 got 3.141592654 expected 3.141592654 sym=ok num=ok [simplify] Unary functions (x = 7/3) ------------------------------------------------------------------------------ exp(x) K=3 d=1 got 10.3122585 expected 10.3122585 sym=ok num=ok [simplify] ln(x) K=7 d=3 got 0.8472978604 expected 0.8472978604 sym=ok num=ok [simplify] -x K=17 d=7 got -2.333333333 expected -2.333333333 sym=ok num=ok [simplify] 1/x K=25 d=8 got 0.4285714286 expected 0.4285714286 sym=ok num=ok [simplify] x - 1 K=11 d=4 got 1.333333333 expected 1.333333333 sym=ok num=ok [simplify] x + 1 K=27 d=9 got 3.333333333 expected 3.333333333 sym=ok num=ok [simplify] 2x K=67 d=17 got 4.666666667 expected 4.666666667 sym=ok num=ok [simplify] x/2 K=51 d=15 got 1.166666667 expected 1.166666667 sym=ok num=ok [simplify] x^2 K=41 d=10 got 5.444444444 expected 5.444444444 sym=ok num=ok [simplify] sqrt(x) K=59 d=16 got 1.527525232 expected 1.527525232 sym=ok num=ok [simplify] Binary operations (x = 7/3, y = 5/2) ------------------------------------------------------------------------------ x + y K=27 d=9 got 4.833333333 expected 4.833333333 sym=ok num=ok [simplify] x - y K=11 d=4 got -0.1666666667 expected -0.1666666667 sym=ok num=ok [simplify] x * y K=41 d=10 got 5.833333333 expected 5.833333333 sym=ok num=ok [simplify] x / y K=25 d=8 got 0.9333333333 expected 0.9333333333 sym=ok num=ok [simplify] x ^ y K=49 d=12 got 8.316526261 expected 8.316526261 sym=ok num=ok [simplify] - genxy - 341311 sekunder sedanI hope this was presented at SIGBOVIK.
- theanonymousone - 341972 sekunder sedanZero will also be handy in definitions: `0=eml(1,eml(eml(1,1),1))`.
And i is obviously `sqrt(-1)`
- zogomoox - 332781 sekunder sedanCould this be used to prove e+pi is transcendental?
- rvnx - 343102 sekunder sedanLooks like he bruteforced all combinations of two mathematical operations no ?
- - 354066 sekunder sedan
- future_crew_fan - 340618 sekunder sedanthere ought to be a special section on HN entitled "things that will make you feel thoroughly inadequate".
- supermdguy - 366252 sekunder sedanNext step is to build an analog scientific calculator with only EML gates
- lifis - 334769 sekunder sedanThe paper somehow seems to be missing the most interesting part, i.e. the optimal constructions of functions from eml in a readable format.
Here is my attempt. I think they should be optimal up to around 15 eml.nodrs, the latter might not be:
# 0
1=1
# 1
exp(x)=eml(x,1)
e-ln(x)=eml(1,x)
e=exp(1)
# 2
e-x=e-ln(exp(x))
# 3
0=e-e
ln(x)=e-(e-ln(x))
exp(x)-exp(y)=eml(x,exp(exp(y)))
# 4
id(x)=e-(e-x)
inf=e-ln(0)
x-ln(y)=eml(ln(x),y)
# 5
x-y=x-ln(exp(y))
-inf=e-ln(inf)
# 6
-ln(x)=eml(-inf,x)
ln(ln(x))=ln(ln(x))
# 7
-x=-ln(exp(x))
-1=-1
x^-1=exp(-ln(x))
ln(x)+ln(y)=e-((e-ln(x))-ln(y))
ln(x)-ln(y)=ln(x)-ln(y) # using x - ln(y)
# 8
xy=exp(ln(x)+ln(y))
x/y=exp(ln(x)-ln(y))
# 9
x + y = ln(exp(x))+ln(exp(y))
2 = 1+1
# 10
ipi = ln(-1)
# 13
-ipi=-ln(-1)
x^y = exp(ln(x)y)
# 16
1/2 = 2^-1
# 17
x/2 = x/2
x2 = x2
# 20
ln(sqrt(x)) = ln(x)/2
# 21
sqrt(x) = exp(ln(sqrt(x)))
# 25
sqrt(xy) = exp((ln(x)+ln(y))/2)
# 27
ln(i)=ln(sqrt(-1))
# 28
i = sqrt(-1)
-pi^2 = (ipi)(ipi)
# 31
pi^2 = (ipi)(-ipi)
# 37
exp(xi)=exp(xi)
# 44
exp(-xi)=exp(-(xi))
# 46
pi = (ipi)/i
# 90+x?
2cos(x)=exp(xi)+exp(-xi))
# 107+x?
cos(x) = (2cos(x))/2
# 118+x?
2sin(x)=(exp(x*i)-exp(-xi))/i # using exp(x)-exp(y)
# 145+x?
sin(x) = (2sin(x))/2
# 217+3x?
tan(x) = 2sin(x)/(2cos(x))
- moralestapia - 330604 sekunder sedanWhoa, this is huge!
My dearest congrats to the author in case s/he shows around this site ^^.
- BobbyTables2 - 369532 sekunder sedanHow does one actually add with this?
- nurettin - 359188 sekunder sedanThe problem with symbolic regression is ln(y) is undefined at 0, so you can't freely generate expressions with it. We need to guard it with something like ln(1+y*y) or ln(1+|y|) or return undefined.
- noobermin - 362561 sekunder sedanI don't mean to shit on their interesting result, but exp or ln are not really that elementary themselves... it's still an interesting result, but there's a reason that all approximations are done using series of polynomials (taylor expansion).
- zephen - 365052 sekunder sedanJudging by the title, I thought I would have a good laugh, like when the doctor discovered numerical integration and published a paper.
But no...
This is about continuous math, not ones and zeroes. Assuming peer review proves it out, this is outstanding.
- mah4k4l - 332883 sekunder sedanAccording to Gemini 3.1 Pro this would shoot the current weather forecasting power through the roof (and math processing in general):
The plan is to use this new "structurally flawless mathematical primitive" EML (this is all beyond me, was just having some fun trying to make it cook things together) in TPUs made out of logarithmic number system circuits. EML would have DAGs to help with the exponential bloat problem. Like CERN has these tiny fast "harcode models" as an inspiration. All this would be bounded by the deductive causality of Pedro Domingoses Tensor Logic and all of this would einsum like a mf. I hope it does.
Behold, The Weather Dominator!
Nördnytt! 🤓